(3x^2+6)=(2x^2-25)

Solution for (3x^2+6)=(2x^2-25) equation:

(3x^2+6)=(2x^2-25)

We move all terms to the left:

(3x^2+6)-((2x^2-25))=0

We get rid of parentheses

3x^2-((2x^2-25))+6=0


We calculate terms in parentheses: -((2x^2-25)), so:

(2x^2-25)

We get rid of parentheses

2x^2-25

Back to the equation:

-(2x^2-25)


We get rid of parentheses

3x^2-2x^2+25+6=0

We add all the numbers together, and all the variables

x^2+31=0

a = 1; b = 0; c = +31;
Δ = b2-4ac
Δ = 02-4·1·31
Δ = -124
Delta is less than zero, so there is no solution for the equation